calculations for a strong DC loop magnet using 1/8" copper capillary tubing:
- OD .125" = 3.1.7mm^2; ID 0.065 -> copper area = 23.2mm^2 ~= AWG 4
- AWG 4 = 0.8 ohms/km
- length of tubing: 30' ~= 40 turns @ 9" each (windings packed into a torus of major radius 1.5"; minor radius 0.5")
- water flow rate through copper capillary tubing: 1 liter/min; assuming we can heat it up from 30C -> 100C, this is 70KCal = 292 KJ/min = 4881 W total. (better pipe it into our hot water heater!)
- 4.8kw / 9m of tubing = 540 W/m
- 540W/m / 8e-4 = 821 A ; V = 821 * 9 * 8e-4 = 5.9V (!!! where the hall am i going to get that kind of power?)
- 821A * 40 turns = 32.8KA in a loop major radius 1.5" = 3.8cm
- magnetic field of a current loop -> B = 0.54T
- lamour radius: 5eV electrons @B = 0.54T : 15um; proton: 2.7cm; electrons @1KeV ~= 2.66e8 (this is close to the speed of light?) r = 3mm.
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